How do I find the expected value and median of a probability density function?

Click For Summary
SUMMARY

The discussion centers on calculating the expected value and median of the probability density function f(x) = (1/2)e^(-x/2) for x > 0. The user seeks clarification on the definitions of expectation and median for continuous random variables. It is established that for f(x) to be a valid probability density function, it must be normalized such that its integral equals 1. The expected value and median can be derived using integration techniques specific to continuous distributions.

PREREQUISITES
  • Understanding of continuous random variables
  • Knowledge of probability density functions (PDF)
  • Familiarity with integration techniques
  • Concept of normalization in probability
NEXT STEPS
  • Learn how to compute the expected value of continuous random variables using integration
  • Study the method for finding the median of a probability density function
  • Explore normalization techniques for probability density functions
  • Review examples of exponential distributions and their properties
USEFUL FOR

Students in statistics, mathematicians, and data scientists seeking to understand the properties of continuous probability distributions and their applications in real-world scenarios.

khansen9
Messages
1
Reaction score
0
TL;DR
TL;Integral
Hey everyone, I have been struggling to find the expected value and median of f(x) = 1/2e^-x/2, for x greater than 0. I am just wondering how I do so? Thank you.
 
Physics news on Phys.org
What are the definitions of the expectation and the median for a continuous random variable? :smile:
 
If f(x) is supposed to be a probability density, then it has to be normalized so its integral = 1.
 

Similar threads

Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K