How Do I Interpret This Graph for Homework?

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To interpret the graph for homework, focus on understanding the relationship between force, time, and motion. The area under the graph represents impulse, which is equal to the change in momentum. Calculating the areas of shapes like triangles and trapezoids can help determine the impulse applied to the object. It's essential to remember that the initial velocity is zero when starting calculations. Using these principles, the final velocity of the toy car can be determined accurately.
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Homework Statement



So should i take the area under the graph or something

Homework Equations


And is in the future i Tackle such problems what are the key thing to remember[/B]

The Attempt at a Solution



Tried subtracting the areas no use xd[/B]
 

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sidt36 said:

Homework Statement



So should i take the area under the graph or something

Homework Equations


And is in the future i Tackle such problems what are the key thing to remember[/B]

The Attempt at a Solution



Tried subtracting the areas no use xd[/B]
Well, what do you know about how force relates to the motion of an object?

Trying random things with a graph rarely leads to anything useful, unless you know something about the physics of what is going on.
 
Well i know that Force * time leads to mass delta velocity
 
Have you done any work with integrals and areas? Integrals and force, momentum and time?
 
sidt36 said:
Well i know that Force * time leads to mass delta velocity
And what sort of calculations did you do with this knowledge, using the graph as a source of data?
 
I added up the areas of the triangle and tapezium
 
And i have not done integrals. I have to solve it with a 9th graders knowledge
 
sidt36 said:
I added up the areas of the triangle and tapezium
Can you share these calculations?
 
As much as i can do
 

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  • #10
sidt36 said:
As much as i can do
Everything looks OK with your calculations, you just need to put them together.

For the first part of the calculation, you are told that the toy car is at rest initially, so this means that v(t) = 0 m/s when t = 0 sec.

What would be the velocity of the car after 4 seconds, using your figures for the change in velocity?

Don't forget to use the mass of the toy car!
 
  • #11
Yup got it 6.5 i cap is the answer
 
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