How do I know if the image is real or virtual?

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To determine if an image is real or virtual, it's essential to analyze the object's position relative to the focal length of the lens. A real image is formed when the object is outside the focal length, while a virtual image occurs when the object is within the focal length. The magnification equation m = - (v/u) can help identify the nature of the image based on its size compared to the object. Diagrams can clarify the relationship between object distance, image distance, and the lens's focal length. Understanding these principles is crucial for accurately identifying image types in optical systems.
izMuted
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Homework Statement


ae476d4f6593d54e328badcc49f9ecd0.png

I know that the object distance is 15 using the equation m = - (v/u)
(+ or - depending on real / virtual) 2 = (+ or -) 30/u
u = 15

However how do I know if the image is real or virtual?

Homework Equations


m = - (v/u)

The Attempt at a Solution

 
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Have you tried drawing the diagram, something like this:
u14l5c1.gif


Where would the image have to be to be bigger than the object?

Which side is known as the real side, which side is known as the virtual side and why?
 
How do I draw the diagram when I don't know if the object is within / outside the focal length?
Also I used to think that because the image is bigger it must be virtual, however there are some diagrams on the internet where the image is bigger and the object is outside the focal length, like here:
u14l5da6.gif
 
"the lens is used as a magnifying glass"- usually when using a magnifying glass is the image virtual or real?
 
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As far as I know, in a converging lens, only when the object is between the optical centre and the focal length that the image is virtual (i.e. the setting used in a magnifying glass).
 
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Ah yeah the magnifying glass part makes sense - thanks for explaining
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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