How do I normalize a wavefunction in three dimensions?

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SUMMARY

The normalization of a wavefunction in three dimensions requires that the integral of the squared wavefunction equals one. The normalization factor, denoted as A, is calculated using the equation A²∫ψ*ψdx = 1. In this case, the integral is evaluated as ∫x⁴e^(-ax)dx, leading to A = √(a⁵/24). The approach for normalizing wavefunctions in higher dimensions follows the same principles as in one dimension, with adjustments for the complexity of the function.

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Lily Wright
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Homework Statement


2. Homework Equations [/B]
Uploaded as a picture as it's pretty hard to type out

The Attempt at a Solution


So to normalise a wavefunction it has to equal 1 when squared.
A is the normalisation factor so we have:
A.x2e-x/2a0.x2e-x/2a0 = 1
∫ψ*ψdx = A2∫x4e-axdx = 1

Then I've been given the integral of this between 0 and ∞: ∫xne-axdx = n!/an+1
∫ψ*ψdx = A2.4!/a5
= A2.24/a5
A = √a5/24

Have I done this right? I don't even know where to start with (ii). Any help would be greatly appreciated!
 

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"." is an unusual multiplication sign, "*" is better (or use LaTeX for the best result).
(i) looks right.

(ii) is like (i), just with a more complicated function and in three dimensions, but the approach is exactly the same.
 

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