How do I prove That Toricelli's equation, given here is correct?

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To prove Torricelli's equation, start with Bernoulli's principle and establish a relationship between the velocities V1 and V2 in terms of the areas A1 and A2. Substitute V2 into Bernoulli's equation, ensuring to include the potential energy term related to height differences. The equation simplifies to show the relationship between the velocities and areas, leading to the expression for V1. Finally, compare the derived equation with the original problem statement to confirm its correctness. Understanding these steps is crucial for solving the problem effectively.
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Homework Statement



The problem is shown here, Problem # 48
Problem-1.jpg




Homework Equations



I know that V1 = Sqrt of 2*G (h)

But the A1^2 / A2^2 part is unknown to me, and I've spent hours trying to find an explanation, but now I'm here...

Can anyone point me in the right direction, please?
 
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Go back to Bernoulli's Principle. Find a relationship between V2 and V1 in terms of the areas. Substitute for V2 in Bernoulli.
 
In Bernoulli's equation I found that

V1 = V2 * A2 / A1
 
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Aliskahir said:
In Bernoulli's equation I found that

V1 = V2 * A2 / A1


Solve that for V2 in terms of V1 (since you're looking to replace V2 in Bernoulli's equation.

Can you write the equation for Bernoulli's principle for this case?
 
(Using D for Density)

If I replace V2 With the equation I get

1/2 DV1^2 + DGY1 = 1/2D (A1*V1/A2)^2 + DGY2

By the way, I appreciate your help, I'm lost mostly because I missed this particular day of class, and I'm trying to understand a friend's notes and the book. My test tomorrow is going to kill me =[
 
Last edited:
Aliskahir said:
(Using D for Density)

If I replace V2 With the equation I get

P1 + 1/2 D V1^2 = P2 + 1/2 D (V1*A1 / A2) ^2

----hold on making revisions---

By the way, I appreciate your help, I'm lost mostly because I missed this particular day of class, and I'm trying to understand a friend's notes and the book. My test tomorrow is going to kill me =[


You're missing the potential energy term (D*g*h) on the left hand side. Remember, there's a height difference between the two locations. P1 and P2 are the ambient air pressure, which can be assumed equal at both locations, so they cancel. Solve for V1.
 
1/2 DV1^2 + DGY1 = 1/2D (A1*V1/A2)^2 + DGY2

1/2 V1^2 (1-A1^2/A2^2) = G (Y2 - Y1)

V1 = Sqrt 2G(Y2-Y1) / (1-A1^2/A2^2)
 
Yeah, I added it up top
 
Is it... correct? or closer to being correct? :confused:
 
  • #10
Aliskahir said:
Is it... correct? or closer to being correct? :confused:

Can't you compare it with what is given in the problem statement?
 
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