How Do I Prove These Mathematical Limit Relations?

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I have been asked to prove the following limit relations.
(a) lim(as x goes to infinity) (b^x-1)/x = log(b)

(b) lim log(1+x)/x = 1

(c) lim (1+x)^(1/x) = e

(d) lim (1+x/n)^n =e^x

Unfortunately, I really have no idea where to start. We have a theorem that says if f(x)=the sum of (c sub n)*(x^n) then the limit of f(x) is the sum of c sub n. Is that useful for this problem? Any suggestions on how to do this?
 
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How rigorous is your class? Do you prove things using the ##\epsilon - \delta## definition or are you simply trying to show that the limits are what they are?
 
For this particular problem, I think we are just supposed to show that they are what they are.
 
mathmathRW said:
For this particular problem, I think we are just supposed to show that they are what they are.

Let's try the first one : ##lim_{x→∞} \frac{b^x-1}{x}##

Try plugging in some values and see what happens for x = 1, 2, 3... . That should draw your attention to what is happening in the numerator depending on ##b##.
 
The "standard" rules of limits are not sufficient here. But you should think about this: what definition of "e" are you using?
 
mathmathRW said:
I have been asked to prove the following limit relations.
(a) lim(as x goes to infinity) (b^x-1)/x = log(b)
That can't be right. If b>1, the exponential function will grow much faster than ##x##, so the limit will diverge.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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