How Do I Solve This Electrical Engineering Equation?

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The discussion focuses on solving an electrical engineering equation using Thevenin's theorem, which is essential for analyzing circuits. Participants suggest using the superposition method if no specific method is required, but emphasize the importance of Thevenin's theorem for this problem. Detailed steps for applying Thevenin's theorem are provided, including how to replace sources and calculate equivalent resistance and voltage. The original poster expresses difficulty with the theorem due to being new to the course and not wanting to post lengthy attempts. Overall, the conversation highlights the need for understanding Thevenin's theorem in circuit analysis.
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Homework Statement



I can't seem to solve this equation from my electrical engineering class.. Can someone please help..


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The Attempt at a Solution


 
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Are you required to use a particular method to solve this network? If not, I would think the superposition method would be a good one to use in this case.

If you make an attempt and show your work, you will get some help.
 
you have to use thevenin's theorem..thats the problem... I am not familiar with it at all..
just started this course..and I am having a really hard time..
my attempt would take too long to post online.. that's why i haven't posted it..
 
Thevenin's theorem procedures:

1) Replace a short circuit instead of the voltage sources and open circuit instead of current sources.

2) Remove the 5 Ohm resistor that you want to calculate the current through it leaving an open circuit instead of the resistor.

3) Calculate the resistance seen from the open that you leave. Call it RTH.

4) Calculate the voltage on the open circuit. Call it VTH.

5) Now draw a practical voltage source (an ideal voltage source in sereis with a resistor) with a voltage of VTH and a resistor value of RTH.

6) Noe return the 5 Ohm resistor. Ix = VTH / (RTH + 5)
 
If the steps is not clear see:

http://www.allaboutcircuits.com/vol_1/chpt_10/8.html
 

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