How do i solve this possibility question

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how do i solve this possibility question

a scientist does 2 experiments, whose outcomes are independant of each other.

the possibility of a positive result in experiment A is 0.9
the possibility of a positive result in experiment B is 0.7

what is the possibility of a positive outcome in at least one of the experiments?

what i think i am looking for is P(A∪B) since i want either P(A) or P(B) or P(A∩B)

the problem is that i don't have enough information,
the answer is 0.97, which is P(A)+P(B)-P(A)*P(B), but how do i get to this, am i wrong in saying that i am looking for P(A∪B) ? which equation can i use to find this answer?
 
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What is the possibility neither experiment has a positive outcome?

How does this help you answer the question?
 
no not really, how can i find that possibility, i know that it is 1-P(A∪B), but how does that help
 
What is the probability of a negative result for each experiment? Then remember that the experiments are independent, so what is the probability that both A is negative and B is negative in terms of each individual probability
 
A negative - 0.1
B negative - 0.3

but from here what do i do, can i say that since they are independant P(A∪B)=P(A)+P(B), but that comes to more than 1,
i see what you are saying, for the negative reult 0.1*0.3, but what rule is this??
 
Assuming A and B are independent, P(A\cap B)= P(A and B)= P(A)P(B).

P(A\cup B)= P(A or B)= P(A)+ P(B)- P(A \cap B)
and that is P(A)+ P(B) only if P(A \cap B)= 0 (A and B are mutually exclusive) which can't be true if they are independent.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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