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## Homework Statement

Use Newton's Method to approximate 96^(1/96) correct to 8 decimal places.

## Homework Equations

Newton's Method equation: Second Approx = (first approx) - (f(first approx))/(f'(first approx))

## The Attempt at a Solution

So I know that 96^(1/96) must = some number x, so I set it up as 96^(1/96)-x=0, but what that does is cause f'(x)=1. This must not be right because when I approximate using this, I get a negative value which is significantly farther away than my first approx. Please help!