Hello, I have a question about mirrors. Wikipedia says, 'Most modern mirrors consist of a thin layer of aluminium deposited at the back of a sheet of glass.' My question is, how does the aluminum at the atomic scale reflect the incident light so precisely? In other words, IF incident photons excite the aluminum's electrons, why do the deexcitations send photons incident at the same angle to the orthogonal as the original? Please keep all discussion to microscopic levels as I know how mirrors work macroscopically. Thanks.