ZapperZ said:
Have you READ the paper?
Zz.
Sorry , no I didn't. I based my comments on DrChinese's description.
Which suggested we could analyse the behaviour of light in two ways.
1. We can regard light as it passes from a donor atom to an absorber
as a wave. The development of the interference patterns then develop
according to classical mechanics as the photon wave passes through
whatever obstructions there might be between source and detector. Of
course in QM the momentum and energy is delivered to the detector,
wherever it is, all at once as an impulse. Our interference pattern
must act as a probability
distribution governing where the photon is likely to be detected.
Here we have use a deterministic method to develop the interference
pattern and then we are forced into interpreting the result as a probability
distribution in order to make any meaningful predictions about where
we are likely to find the photon. In effect we have to break the
causal chain once we have determined the interference pattern for
that particular experimental situation.
2. The second way is to assume the photon is a particle. If we
take Young's double slit experiment the particle must go through one
or other of the slits or at least if we place detectors in the slits
we will find the photon only at one of them. Assuming a symmetrical
arrangement there will be a 50% chance of finding the photon in one or
the other of the slits. When the photon passes through a slit it's
position in a direction at right angles to the slit is precisely
fixed, HUP then demands that the component of the momentum in that
direction is completely uncertain. From either of the slits the photon
has an equal probability of taking a path at any angle from zero to
180 degrees. However since there are two slits and the photon has an
equal chance of going through either; the position of the photon as it
goes through the slits is not precisely fixed, it can still go through
either one. This increases in uncertainty with respect to position
allowing the uncertainty in momentum to be reduced. The information
we need to calculate the reduction in uncertainty is contained in the
equation p = h/wavelength. And the knowledge that even though the
component of momentum at right angles to each of the slits is
completely unknown the overall magnitude of the momentum will be
unaffected when the photon passes through the slits. For every
possible path demanded by HUP we can plot along the path the intensity
of the particle's momentum. By combining the results from the two
slits, this will allow us to obtain the same probability density
pattern as the interference pattern we would have had if we had had
assumed the photon to be a wave initially.
I hope I've got the general idea right, otherwise please put me right.
Unfortunately this solution throws up many new questions. One of
which I would like to be discussed.
How can the probability distributions from the two slits interfere
with each other? Does this mean somehow under the cloak of uncertainty
the particle is actually taking all possible routes and existing at
more than one place simultaneously and at anyone place and time there
is more than one version of the particle? Or does it mean some how the
probabilities are built into the experimental arrangement and the
particle with a given momentum just follows the normal laws of
probability?
May be that's three questions, just counting the ?'s ?