How Do Pressure and Standing Waves Change with Distance and Interaction?

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A Helmholtz resonator with a resonant frequency of 100Hz produces pressure and displacement variations that can be graphed over time. At a distance from the resonator, the listener experiences a modified version of these waves due to energy loss and propagation effects. Standing waves are formed when traveling waves move in opposite directions, leading to interference patterns that can cancel out at certain points. The frequencies of these standing waves are directly related to the wave speed on a string, which depends on the string's tension and linear mass density. Understanding these concepts is crucial for analyzing wave behavior in different contexts.
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Hi there

Could someone please help with these questions.

A helmholtz resonator has a resonant freq. of 100Hz. draw graphs showing how the pressure and displacement of the air in the neck vary with time. how would these be different at the position of a listener some distance away...

i can draw the graphs but I'm unsure of the part about the listener being some distance away...??

and the 2nd one is ...explain how a standing wave can be formed by traveling waves, and hence how the frequencies of standing waves on a stretched string are related to the speed at which waves travel along the string?

all i know is that waves would be traveling in opposite directions..canceliing out..? is this even right?...any help much appreciaited

Thanks
physics_06er
 
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-1- The resonator will have a partial standing wave in it (partial because some of the sound energy has to get out the open end to propagate to the listener.

-2- What is the equation for a traveling wave? What do you get if you combine a left-travelling wave and a right-travelling wave? Also, what is the relationship between the velocity of propagation of a wave on a string, in comparison to the tension of the string and the linear mass density of the string?
 
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