How do you binomially expand this?

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The discussion focuses on expanding the expression (x^2 + y^2)^0.5 using the generalized binomial theorem. The theorem states that (x + y)^\alpha can be expressed as an infinite series involving generalized binomial coefficients when α is not a positive integer. For the specific case of α = 1/2, the expansion translates to (x^2 + y^2)^\alpha being represented as an infinite series of terms involving x raised to even powers and y raised to corresponding powers. The generalized binomial coefficient is defined for this case, allowing for the calculation of each term in the series. This method provides a systematic approach to binomial expansion for non-integer exponents.
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(x^2+y^2)^0.5
 
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You can look at the "generalized binomial theorem" here:
http://en.wikipedia.org/wiki/Binomial_series

Basically, it says that
(x+ y)^\alpha= \sum \left(\begin{array}{c}\alpha \\ i\end{array}\right)x^i y^{\alpha- i}
where
\left(\begin{array}{c}\alpha \\ i\end{array}\right)= \frac{\alpha(\alpha+ 1)(\alpha- 2)\cdot\cdot\cdot(\alpha- i-1)}{i!}
is the "generalized binomial coefficient". If \alpha is a positive integer, the "generalized binomial coefficient" is the usual binomial coefficient and is eventually 0 so the sum is finite. If \alpha is not a positive integer (and for your problem, it is 1/2) the sum is an infinite series.

With x^2 and y^2 instead of x and y, it just becomes
(x^2+ y^2)^\alpha= \sum \left(\begin{array}{c}\alpha \\ i\end{array}\right)x^{2i} y^{2(\alpha- i)}
 
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