How Do You Calculate Acceleration and Travel Distance from Velocity-Time Graphs?

AI Thread Summary
To calculate acceleration and travel distance from velocity-time graphs, the area under the graph represents the distance traveled. In the scenario presented, a car accelerates from 10 m/s to a speed of Vm/s over time T, then maintains that speed before accelerating again to 20 m/s. The total distance from point A to D is given as 675 m, which can be determined by summing the areas of the segments on the graph. By applying simultaneous equations and analyzing the graph, the values for acceleration (a) and time (T) can be derived. The discussion concludes with the user successfully finding the solution with the provided guidance.
New2Science
Messages
2
Reaction score
0
As a car passes point A on a straight road, it's speed is 10m/s, the car moves with constant acceleration, a m/s/s, along the road for T seconds until it reaches point B, where it's speed is Vm/s.
The car travels at this speed for a further 10 seconds, when it reaches the point C. From C it travels for a further T seconds with constant acceleration 3a m/s/s until it reaches a speed of 20 m/s at the point D.

Sketch the [t,v] graph for the motion, and show that V=12.5

I had no problem with showing V = 12.5 through a simultaneous equation.

However part B states,
The distance from A to D is 675m, find a and T

Any help will be so very greatly appreciated!
Thanks in advance
New2Science
 
Last edited:
Physics news on Phys.org
The area under the graph of velocity is the distance traveled. The area, as should be obvious from the sketch, is a sum of three simple areas. Together with the equation you used for velocity, you should be able to determine a and T from it.
 
If you can sketch the [t,v] graph for the motion, then you can deduce the answer.
The area under the graph is the distance.
 
Thanks a lot for the help!

I got it now (:

Thanks Again
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top