How Do You Calculate Equilibrium Concentrations in a Redox Reaction?

AI Thread Summary
The discussion revolves around calculating equilibrium concentrations for a redox reaction involving Fe2+ and Cr2O72-. The equilibrium constant is given as 1×10^57, and the initial concentrations of the reactants are specified. Participants express confusion regarding the concentrations of Cr3+ and Fe3+, particularly whether the provided concentration of K2Cr2O7 refers to Cr2O72-. It is suggested that dilution may be a factor affecting the calculations, and there is a potential error in the text regarding the concentration of Cr2O72- at equilibrium. Clarification on these points is needed for accurate calculations.
cliffordlim
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Homework Statement


Fe2+and Cr2O72- react as follows: 6Fe2+ + Cr2O7 2− + 14H + >>> 6Fe3+ + 2Cr3+ + 7H2O.

The equilibrium constant for the reaction is 1×10^57. Calculate the equilibrium concentrations

of the iron and chromium species if 10 mL each of 0.02M K2Cr2O7 in 1.14M HCl and 0.12M FeSO4

in 1.14M HCl are reacted.

Homework Equations




The Attempt at a Solution


https://physicsforums-bernhardtmediall.netdna-ssl.com/data/attachments/97/97696-2f7ec586395970f64d734682baf6f166.jpg

This is the solution provided . I still don't understand as Cr3+ is 0.02M in the equation as the question give is K2Cr2O7 is 0.02M > does it mean 0.02M of Cr2O72- ? Same goes to iron .
 

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cliffordlim said:
I still don't understand as Cr3+ is 0.02M in the equation as the question give is K2Cr2O7 is 0.02M > does it mean 0.02M of Cr2O72-

Elaborate please, I have no idea what you mean.

Chances are you are forgetting about dilution, but that's just a wild guess.
 
I think there is a mistake in the text; when it says "At equilibrium 0.02 mol/L Cr2O72- has reacted..." that should be 0.01 mol/L Cr2O72-. Is that the problem? I think the expression here is unclear. But then you say "same goes to iron". Are you just forgetting about dilution, as Borek suggests?
 
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