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tylerm2010
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Homework Statement
1800 HP motor
spins at 6600 RPM
FIND:
3 stage reduction (and 90deg turn up) to main rotor to spin at 300 RPM
2 Stage reduction (and 90deg turn to the side) to tail rotor to spin at 1700 RPM
Homework Equations
torque = 525*HP/RMP
Saftey factor = 2
Loading condition = 2
The Attempt at a Solution
I solved for the engine torque using the equation above and got 1433 ft.lbs
Gear reduction needed to the main rotor is 22:1
Gear reduction needed to the back rotor is 3.88:1
I am not concerned with bearings, backlast...only the gear reductions and that the teeth will not break under the loads from the engine.
Any help at how to solve this would be great.