How Do You Calculate Impulse and Force in a Rear-End Collision?

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The impulse on the man in the rear-end collision is calculated as 225 Ns, derived from his mass and change in velocity. The net force acting on him is 1125 N, calculated using the impulse and the time interval of 0.2 seconds. Acceleration during the collision is determined to be 15 m/s². The discussion highlights a challenge in calculating the total impulse for both the man and the car without knowing the car's mass. Seeking assistance to express the impulse in terms of the car's mass is suggested.
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A 75 kg man is sitting in his car at rest at the stoplight. He is rear-ended by another car and is accelerated to 3.0 m/s in 0.2s. What is the impulse on the man and his car?

I found the impuse on the man which was:

I = m(change v)

= 75(3.0 -0)
= 225 Ns

I found the Net force on the man:

Fnet = 225/change in time
=225/0.2s
=1125N

I also found acceleration which is 15 m/s^2

I'm stumped because I can't find a way to find the impulse of the man and the car without needing the mass of the car. Any help would be highly appreciated.

Thank you
 
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are those the exact words of the problem?

perhaps the answer is in terms of m?
 
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