How Do You Calculate Moles of Water Vapor in Air Using Ideal Gas Law?

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To calculate the moles of water vapor in air using the Ideal Gas Law, the relative humidity of 55% at 30.0°C corresponds to a vapor pressure of 4200 Pa. The temperature must be converted to Kelvin, resulting in 303 K. The formula n/v = p/RT is applied, where p is the vapor pressure, R is the gas constant (8.32 J/(mol·K)), and T is the temperature in Kelvin. Using these values, the calculation yields approximately 1.67 mol/m³. Further clarification is needed on converting the results to the desired units.
owura143
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The relative humidity is 55% on a day when the temperature is 30.0°C. Using the graph below, determine the number of moles of water vapor per cubic meter of air.


on the graph, Vapor pressure of water is on the y-axis and temperature on the x-axis 30C cordinates with 4200 Pa of water vapor.


This how i tried to sove it.

Since 30 corresponds to 4200 Pa

T in Kelvin =303
n/v = p/RT
=4200/(8.32 x 303)
= 1.67
 
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I need help with this same problem...

http://www.webassign.net/CJ/12_76.gif

That is the graph, if anyone can help.

EDIT... I really don't know where to start at all. I tried to do it (almost) the same way as owura, but I couldn't figure it out how to find it in "mol/m^3".
 
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