How Do You Calculate Relative Speed of Particles Moving Orthogonally in Physics?

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To calculate the relative speed of two particles moving orthogonally in physics, one must consider their velocities in a given inertial frame. When two particles are shot out simultaneously at speed u in orthogonal directions, the speed of each particle relative to the other can be derived using the formula Ur = u*[2 - (u^2/c^2)]^0.5. This approach avoids the use of 4-vectors and instead relies on understanding the transformation of velocities in special relativity. By analyzing the situation from the frame of one particle, the effects of Lorentz transformations on their velocities can be effectively illustrated. Understanding these principles is crucial for solving problems involving relative motion in the context of special relativity.
pinky86
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I'm having trouble picturing the following problem.

In a given inertial frame, two particles are shot out simultaneously from a given point, with equal speed u, in orthogonal directions.

a) Without using 4-vectors show that the speed of each particle relative to the other is given by:

Ur=u*[2-{(u^2)/(c^2)}]^0.5
 
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Call the given frame S'. In that frame, imagine that one particle (B) is moving with velocity +u along the y-axis; the other particle (A) is moving with velocity -u along the x-axis.

Now view things from the frame of particle A, which you can call S. Note that S' moves with speed +u along the x-axis in frame S. (The usual set up for Lorentz transformations.)

How do velocities transform in special relativity?
 
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