How Do You Calculate Tension in a Wire When a Model Airplane Flies in a Circle?

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To calculate the tension in a wire when a model airplane flies in a circle, one must consider the forces acting on the airplane, including tension, gravitational force, and aerodynamic lift. The airplane has a mass of 0.760 kg, flies at a speed of 35.0 m/s, and the control wire makes a 20.0° angle with the horizontal. The centripetal acceleration is calculated using the radius of the circle, which is determined to be 54.40 m, leading to a centripetal acceleration of 22.47 m/s². The equations for summing forces are established, but discrepancies in calculations suggest that careful attention to the relationships between forces and angles is necessary to arrive at the correct tension value. Ultimately, the discussion emphasizes the importance of accurately applying physics principles to solve for tension in this scenario.
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Model Airplane Question - centripetal acceleration and summing forces

A model airplane of mass 0.760 kg flies in a horizontal circle at the end of a 58.0 m control wire, with a speed of 35.0 m/s. Compute the tension in the wire if it makes a constant angle of 20.0° with the horizontal. The forces exerted on the airplane are the pull of the control wire, the gravitational force, and aerodynamic lift, which acts at 20.0° inward from the vertical as shown in Figure P6.71.

OK, I've been working on this one for 20 minutes and i have no idea. last question left on my problem set.

I found the centripetal acceleration by finding the radius of the circle in which the plane flies--since it flies on an angle on the string, i found this to be 54.40 m (NOT the 58m from the question--is this right?) my centripetal Acceleration was 22.47m/s^2

Next i summed the forces, got
SUM(Fr)=> Ac = Fsin(theta)+Tcos(theta)
SUM(Fy)=> Tsin(theta)+W=Fcos(theta)

from here i solved the 2nd equation for "F" and pluged it into the first, solved for t. I got 18.56, which is wrong. Any ideas? I am sure i missed some thing small, thanks for the help!
 

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Fc = Tcos20 + Flsin20

mg = -Tsin20 + Flcos20 with Fl = life, surely?

I don't think you have to solve for Fl, just calculate Fc then get Fl in terms of T and just solve for T.

Do you know what the answer should be?

Sorry - edited after looking more closely at picture...
 
rsk said:
Fc = Tcos20 + Flsin20

mg = -Tsin20 + Flcos20 with Fl = life, surely?

I don't think you have to solve for Fl, just calculate Fc then get Fl in terms of T and just solve for T.

Do you know what the answer should be?

Sorry - edited after looking more closely at picture...

that is effectively what i did. i got Fl in terms of T and plugged it in, had the same equations you did. no, don't know what the answer should be, it is an online webassign assignment which you get 5 chances to get the right answer. i have 3 wrong so far
 
rsk said:
Fc = Tcos20 + Flsin20

mg = -Tsin20 + Flcos20 with Fl = life, surely?

I don't think you have to solve for Fl, just calculate Fc then get Fl in terms of T and just solve for T.

Do you know what the answer should be?

Sorry - edited after looking more closely at picture...

is Fc the same as centripetal acceleration? v^2/r?
 
You wrote:

SUM(Fr)=> Ac = Fsin(theta)+Tcos(theta)

while you probably ment

SUM(Fr)=> Fc = Fsin(theta)+Tcos(theta)

where

F_C = \frac{mv^2}{r}

I did follow the same procedure as you but got a different answer.
Best you show all the steps so that we can comment on your work.

What is very interesting about my final formula - just before calculating the tension in the string - is that this formula suggest that if the airplane flew in a circle inclined at 20^o to the horizontal (in the plane of the direction of the sting, that is if the hobbyist stood on a platform and let it fly in a plane inclined at twenty degrees w.r.t. the horizontal in stead of a horizontal plane as in the problem) with the same speed the tension (when the airplane is at the top of this inclined plane- at point B) would be exactly the same as the case is with the stated problem you are trying to solve.
 
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