How Do You Calculate the Acceleration and Direction of a Flea in a Breeze?

AI Thread Summary
To calculate the acceleration and direction of a flea in a breeze, first determine the weight of the flea using its mass and gravity, which is 5.88 X 10-6 N. The net forces in the x and y directions must be analyzed separately, with the breeze force acting horizontally and the flea's force and weight acting vertically. The equations netFy = Fflea - weight and netFx = Fbreeze can be used to find the accelerations in both directions. The resulting accelerations are approximately 10.2 m/s² in the y direction and 0.83 m/s² in the x direction. Finally, use Pythagorean theorem and trigonometry to find the overall magnitude and direction of the flea's acceleration.
jfeyen
Messages
7
Reaction score
0

Homework Statement



A flea jumps by exerting a force of 1.20 X 10-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of 0.500 X 10-6 N on the flea. Find the direction and magnitude of the acceleration of the flea if its mass is 6.00 X 10-7 kg. Do not neglect the force of gravity.


Homework Equations



a= net F / m
w=mg


The Attempt at a Solution



I went ahead and found the weight of the flea by multiplying its mass times gravity (6X10-7)(9.8)= 5.88X10-6 N which I'm assuming will be figured into the net F, but I'm not sure exactly where to go from here. Does weight need to be subtracted from the force of the flea on the ground and the force of the breeze on the flea? or does the weight and the force of the flea need to be subtracted from the force of the breeze? am I on the wrong track all together?? Do I need to somehow break it down into x and y components.. in which case I'm more lost than I thought. :)

Also, I suppose the weight needs to be figured into the direction? I tried tan-1(.5X10-6/1.2X10-5) for an angle of 2.39o but the answer in the back of the book is 4.68o so obviously I don't know what I'm doing.

Thank you in advance for any help :)
 
Physics news on Phys.org
The breeze force acts in the x direction, while the weight and ground forces act in the y direction. You have to look at the net forces in the x direction to solve for the acceleration in the x direction, then look at the net force in the y direction to solve for the acceleration in the y direction. Then the acceleration magnitude and direction comes from pythagorus' theorem and basic trig.
 
I guess I'm just having problems figuring out how to deconstruct this then. I think I was close to having everything snap into place in my mind, but it's gone. Is this the right idea? netFy= Fflea-w= may... ay= 10.2m/s2? and netFx= Fbreeze= max... ax= .83m/s2?
 
jfeyen said:
I guess I'm just having problems figuring out how to deconstruct this then. I think I was close to having everything snap into place in my mind, but it's gone. Is this the right idea? netFy= Fflea-w= may... ay= 10.2m/s2? and netFx= Fbreeze= max... ax= .83m/s2?
Yes, exactly (I didn't check your numbers, but your equations are correct).. Just be a bit more clear on the direction... Fnety is up...so ay is up..now solve for the mag and direction of a.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top