How Do You Calculate the Area Bounded by \( r = 8\cos(10\Theta) \)?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
4 replies · 4K views
Cici2006
Messages
7
Reaction score
0

Homework Statement


Find the area of the region bounded by r=8cos10[tex]\Theta[/tex]


Homework Equations





The Attempt at a Solution



I set r=0 to find [tex]\Theta[/tex], which i used for my bounds
[tex]\Theta[/tex]=pi/20, 3pi/20
A= [tex]\int[/tex](1/2)64cos^2(10[tex]\Theta[/tex]) d[tex]\Theta[/tex]
 
Last edited:
Physics news on Phys.org
What you need to do is multiply your answer by 20 since you found the area of one of the 20 petals of the rose curve.
 
Are you having trouble finding the correct solution since yours is too small? or because you don't know how to evaluate the integral?

If you need help evaluating the integral, use the fact that

[tex]\cos^2{nx} = \frac{1+\cos{2nx}}{2}, n\in\mathbb{N}[/tex]
 
Okay, let me state what i did in more detail:
A=(1/2)integral 64(cos^2(10theta)) d(theta)
=32 integral (1/2)(1+cos20theta) (theta)
=16[theta-(1/20)sin20theta]
did i do it correct so far?
then i just plug in my bounds which are pi/20 to 3pi/20 right?
now should i just multiply my answer by 20?