How Do You Calculate the Eccentricity of an Elliptical Orbit?

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To calculate the eccentricity of an elliptical orbit, knowing the semi-major axis and the aphelion distance is essential. The aphelion distance is equivalent to the radius of Earth's orbit in this case. By determining the perihelion distance using the relationship between aphelion, perihelion, and the major axis length, eccentricity can be calculated. The formula for eccentricity involves the distances of aphelion and perihelion. Understanding these relationships allows for accurate eccentricity determination in orbital mechanics.
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##\mu_{sun} = 132712000000##
##\mu_{earth} = 398600##
##\mu_{mars} = 42828##
##R_{earth} = 149.6\times 10^6##
##R_{mars} = 227.9\times 10^6##
##r_{earth} = 6378##
##r_{mars} = 3396##

The spacecraft will make 3 rev in 2 Earth years. I found the semi-major axis of the ellipse which is
$$
a = 1.14162979\times 10^8
$$
How can I determine the eccentricity of the ellipse with this information? I have been looking at every formula but can figure it out.

http://img20.imageshack.us/img20/182/orbit2.png
 
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If you know the aphelion distance and the length of the major axis then you can determine the perihelion distance. Having both ra and rp you can determine eccentricity.
 
I wasn't thinking thanks.
 
From your drawing the aphelion of the spacecraft is the same as the radius of Earth's orbit.
And the sum of aphelion and perihelion is equal to the length of the major axis.
 
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