How Do You Calculate the Electric Field to Suspend a Proton?

[EtherMD]

Homework Statement

A proton (m=1.67x10^-27) is suspended at rest in a uniform electric field E. Take into account gravity and determine E.

Homework Equations

F_E=|q|E
F_g=mg

The Attempt at a Solution

F_G = mg
F_G = (1.67x10^-27)(9.8)
F_G = 1.64 x 10^-26

Since the force on the proton due to the E field is equal and opposite, then:
F_E=|q|E
F_E / q= E
(1.64x10^-26) / (1.6x10^-19) = E
1.04x10^-9 = E


Is my work correct?

 

[LowlyPion]

Since the force on the proton due to the E field is equal and opposite, then:
F_E=|q|E
F_E / q= E
(1.64x10^-26) / (1.6x10^-19) = E
1.04x10^-9 = E

Have you handled your exponents correctly?

 

[EtherMD]

Probably not, but does the way I reached my answer make sense?

 

[Defennder]

Yes the steps are correct, just a calculation error.