How Do You Calculate the Final Temperature of a Metal and Water Mixture?

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To calculate the final temperature of a metal and water mixture, the heat lost by the metal must equal the heat gained by the water, assuming no heat loss to the environment. The formula used is heat energy = mass * (final temperature - initial temperature) * specific heat. For the metal, the initial temperature is 100°C, and for the water, it starts at 20°C. By setting the heat energy equations for both substances equal, the final temperature can be determined. This approach ensures accurate calculation of the final equilibrium temperature in the mixture.
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A 1.0kg sample of metal with a specific heat of 0.50 KJ/KgC is heated to 100.0C and then placed in a 50.0g sample of water at 20.0C. What is the final temperature of the metal and the water?



Heat energy=mass*(Final temp.-initial temp.)*Specific Heat



i have no idea how to even start
 
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Let the initial temp. of the metal be \theta

Assuming no heat losses,all the heat from the metal goes into increasing the temperature of the water.

Heat energy=mass*(Final temp.-initial temp.)*Specific Heat

Find the heat energy the metal has when it's final temperature is 100 and initial is \theta.

For the water, the initial temperature is 20. Can you find a similar expression for heat energy?
 
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