How Do You Calculate the Final Temperature of a Metal and Water Mixture?

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The discussion focuses on calculating the final temperature of a metal and water mixture using the principle of conservation of energy. A 1.0 kg metal sample with a specific heat of 0.50 kJ/kg°C is heated to 100.0°C and placed in 50.0 g of water at 20.0°C. The heat energy equations for both the metal and water are established, leading to the conclusion that the heat lost by the metal equals the heat gained by the water, allowing for the determination of the final equilibrium temperature.

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A 1.0kg sample of metal with a specific heat of 0.50 KJ/KgC is heated to 100.0C and then placed in a 50.0g sample of water at 20.0C. What is the final temperature of the metal and the water?



Heat energy=mass*(Final temp.-initial temp.)*Specific Heat



i have no idea how to even start
 
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Let the initial temp. of the metal be [itex]\theta[/itex]

Assuming no heat losses,all the heat from the metal goes into increasing the temperature of the water.

Heat energy=mass*(Final temp.-initial temp.)*Specific Heat

Find the heat energy the metal has when it's final temperature is 100 and initial is [itex]\theta[/itex].

For the water, the initial temperature is 20. Can you find a similar expression for heat energy?
 

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