How Do You Calculate the Final Temperature of a Metal and Water Mixture?

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A 1.0kg sample of metal with a specific heat of 0.50 KJ/KgC is heated to 100.0C and then placed in a 50.0g sample of water at 20.0C. What is the final temperature of the metal and the water?



Heat energy=mass*(Final temp.-initial temp.)*Specific Heat



i have no idea how to even start
 
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Let the initial temp. of the metal be [itex]\theta[/itex]

Assuming no heat losses,all the heat from the metal goes into increasing the temperature of the water.

Heat energy=mass*(Final temp.-initial temp.)*Specific Heat

Find the heat energy the metal has when it's final temperature is 100 and initial is [itex]\theta[/itex].

For the water, the initial temperature is 20. Can you find a similar expression for heat energy?