How Do You Calculate the Initial Speed of a Bullet After It Embeds in a Block?

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To calculate the initial speed of a bullet after it embeds in a block, one can use the conservation of energy principle. The bullet, with a mass of 8.00g, strikes a block of mass 0.992kg, compressing a spring by 15.0cm. The spring constant can be determined using the force required to compress it, which is 0.750N for 0.250cm, leading to a spring constant (k) of 30N/m. The kinetic energy of the block just after the impact can be equated to the work done on the spring to find the block's velocity. Using these calculations, the initial speed of the bullet can be derived effectively.
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Homework Statement



A rifle bullet with mass 8.00g strikes and embeds itself in a block with mass 0.992kg that rests on a frictionless, horizontal surface and is attached to a coil spring. The impact compresses the spring 15.0cm. The callibration of the spring shows that a force of 0.750N is required to compress the spring 0.250cm.
(a) find the magnitude of the block's velocity just after impact.
(b) what is the initial speed of the bullet?

Homework Equations


mass(bullet)=8.00g
mass(block)=0.992g
compression=15.0cm
1/2mu^2+1/2mv^2 = KE
Work done(spring)= 1/2kx^2

The Attempt at a Solution



(a) I tried 1/2mv^2=KE(SINCE u=0)
I then got v~26.83
(b) I guess the best attempt is of using the law of conservation of energy relating KE to the Work done(spring)
i am not sure of this trial because i don't know k, also is it wise for me to look at the initial velocity of the system as large?
 
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You do know k. F=kx. I am sure with k you know all you need with conservation of energy.
 
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