How Do You Calculate the Initial Velocity Components of a Projectile?

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Homework Help Overview

The discussion revolves around calculating the initial velocity components of a projectile given its horizontal and vertical displacements after a certain time. The problem involves understanding projectile motion, specifically the relationships between displacement, velocity, and acceleration due to gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations of motion for horizontal and vertical displacements, questioning the assumptions about initial velocities and the effects of gravity. There are attempts to derive the initial velocity components based on given displacements and time.

Discussion Status

Participants are actively engaging with the problem, offering equations and discussing the implications of their assumptions. Some have calculated the horizontal component of velocity, while others are working on the vertical component. There is a recognition of the need to clarify the role of gravity and the initial velocity in the equations.

Contextual Notes

There is an ongoing debate about the initial conditions of the projectile, particularly whether the initial vertical velocity can be assumed to be zero. Participants are also navigating the implications of using negative signs in their calculations related to gravity.

  • #31
So the horizontal component of my initial velocity is 20 m/s, and the vertical component of initial velocity is 36.6 m/s
 
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  • #32
Now i have to calculate how far is its displacement horizontally from launch pt, at the instant it achieves max height.

So i know that its v will be 0 m/s at max heigh.
 
  • #33
kara said:
So i know that its v will be 0 m/s at max heigh.
Right... the vertical component of the velocity will be zero.
 
  • #34
and b/c I am looking for how far its been displaced horizontally from the launch pt. i am looking for x?
 
  • #35
so i can solve for t in the y=y0 + v0-1/2gt^2 equation and sub t into x=x0 +v0t equation and solve for x
 
  • #36
kara said:
and b/c I am looking for how far its been displaced horizontally from the launch pt. i am looking for x?
That's right. You are looking for the value of x when y is maximum. Hint: When does it reach the maximum height?
 
  • #37
well the max height is 53 m, and it reaches that height when v = 0.0 m/s
 
  • #38
i plugged in all my values but get stuck at one point with a negative square root:

53 = -1/2(9.8)t^2
 
  • #39
if i multiply both sides by 2 to get rid of the 1/2 i get

106 = -(9.8) t^2
 
  • #40
kara said:
i plugged in all my values but get stuck at one point with a negative square root:

53 = -1/2(9.8)t^2
You left out part of that equation; it should be:
53 = v0t -1/2(9.8)t^2

Where v0 is the vertical component of initial velocity that you found earlier.
 

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