How Do You Calculate the Interest Rate for Compound Interest Problems?

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Discussion Overview

The discussion revolves around calculating the interest rate for compound interest problems, specifically focusing on the mathematical steps involved in deriving the interest rate from given future and present values, as well as the number of compounding periods. Participants are exploring the underlying concepts and calculations required to understand the process better.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant presents a problem involving future value (FV), present value (PV), and the interest rate (R), expressing confusion about the mathematical steps to isolate R.
  • Another participant explains the concept of taking roots in mathematics, specifically how to "cancel" the operation of raising to a power by taking the corresponding root.
  • There is a clarification about the notation used for the twelfth root, with a participant correcting the misunderstanding regarding the representation of the root operation.
  • Some participants request a more detailed, step-by-step explanation of the calculations involved, indicating a desire for clarity in the mathematical process.
  • One participant expresses gratitude for the explanations but reiterates their struggle with the concepts, asking for further elaboration on the calculations.
  • Another participant provides a definition of the cube root, emphasizing the importance of understanding such foundational concepts in relation to the problem at hand.
  • There are expressions of appreciation for the patience shown by others in the discussion, indicating a supportive atmosphere despite the challenges faced by the novice participant.

Areas of Agreement / Disagreement

The discussion reflects a lack of consensus on the clarity of the mathematical explanations provided, with some participants feeling that the explanations are not sufficiently detailed for novices. Multiple viewpoints on how to present the calculations and concepts exist, indicating ongoing uncertainty and a need for further clarification.

Contextual Notes

Participants express varying levels of mathematical understanding, which affects their ability to follow the explanations. There are requests for long-hand calculations and foundational definitions, highlighting the need for tailored explanations based on individual backgrounds.

Who May Find This Useful

This discussion may be useful for individuals preparing for investment exams, those seeking to understand compound interest calculations, and novices in mathematics looking for step-by-step guidance on related concepts.

iksotof
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Have this question in relation to some investment exam I am doing, I am a maths novice being some years since leaving school etc, ok enough of the excuses.

Example

FV = future value
PV = present value
R = interest rate
N = number of compounding periods


my PV is 6000 and my FV is 10000. Compounding periods is 12, I need to find the interest rate, thus...

100000 = 6000 (1 + R) to power of 12 (sorry don't know how to represent that on key board).


substitution: 1.67 = (1 + R) power 12


substitution 2: 12√1.67 = 1 + R

1.0435 - 1 = R

R = 4.45.

All very well, but I lose understanding of how the maths is applied at sub 2, my textbook
has given this model answer. For a novice please show me step by step what


12√1.67 means.


Thanks you Darren.
 
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Okay, to "cancel" the operation of cubing a number, you need to to take the cube root in order to get back to your number.

That is we have for any number a:
[tex]\sqrt[3]{a^{3}}=a[/tex]
(Taking the cube root of a cube leaves you with the original number "a")

Similarly, if a positive number "a" is raised to the twelfth power, you must take the twelfth root to get a back:
[tex]\sqrt[12]{a^{12}}=a.[/tex]

Now, how to use this in your present case`

WEll, you are to solve for R, but that appears in your equation within the expression [itex](1+R)^{12}[/tex]<br /> <br /> Now, you are ALLOWED with an equation to "do" whatever operation you like, AS LONG AS YOU DO THE SAME ON BOTH SIDES!.<br /> <br /> Thus, in order to remove the twelfth power on the right hand side (increasing your chances to solve for R!), you take the twelfth root of both sides.<br /> <br /> <br /> That's what the second substitution does.[/itex]
 
iksotof said:
Have this question in relation to some investment exam I am doing, I am a maths novice being some years since leaving school etc, ok enough of the excuses.

Example

FV = future value
PV = present value
R = interest rate
N = number of compounding periods


my PV is 6000 and my FV is 10000. Compounding periods is 12, I need to find the interest rate, thus...

100000 = 6000 (1 + R) to power of 12 (sorry don't know how to represent that on key board).
Using just the keyboard, 100000= 6000(1+R)^(12). Using "html" tags, 100000= 6000(1+R)12. Using "LaTex" [itex]100000= 6000(1+ R)^{12}[/itex]. But you don't mean "100000" on the left, only 10000.

substitution: 1.67 = (1 + R) power 12
Dividing both sides by 6000, 10000/6000= 10/6= 4/3 which is 1.67 to two decimal places.

substitution 2: 12√1.67 = 1 + R

1.0435 - 1 = R

R = 4.45.

All very well, but I lose understanding of how the maths is applied at sub 2, my textbook
has given this model answer. For a novice please show me step by step what

Thanks you Darren.

12√1.67 means.[/quote]
It means the "twelfth root of 1.67", not "square root"! The "twelfth root of x" is defined as the number whose 12 power is x- that's why [itex]^{12}\sqrt{(1+R)^{12}}= !+R[/itex]. To actually do the that on a calculator, if you have a "^", power, key, use the "1/12 power": 1.67 ^ (1/12). If your calculator does not have a "^" key you will need to use logarithms. log(x^{1/12})= (1/12)log x= log x/12. To find the 12th root of 1.67, take the logarithm of 1.67, divide by 12, the use the "inverse" to logarithm: 10^ if you are using common logs
 
[itex]^{12}\sqrt{(1+R)^{12}}[/itex], rather: [itex]\sqrt[12]{(1+R)^{12}}[/itex]

:smile:
 
Thank you greatly but I am a total novice and whilst I am sure your explanation is clear to a knowledgeable person, I am not, in isolation therefore it doesn't mean a great deal. Could you maybe show the maths in long hand please? For example 2 cubed is 2 x 2 x 2=
8.

Please continue with this long hand through the remainder.


Thanks again Darren.
 
Yes, and tell me:

What is the definition of the cube root of a number?
 
iksotof said:
Thank you greatly but I am a total novice and whilst I am sure your explanation is clear to a knowledgeable person, I am not, in isolation therefore it doesn't mean a great deal. Could you maybe show the maths in long hand please? For example 2 cubed is 2 x 2 x 2=
8.

Please continue with this long hand through the remainder.


Thanks again Darren.
Continue with what? 23= 8 exactly as you said. If you want us to now find [itex]\sqrt[3]{8}[/itex] (thanks, arildno)? There is no calculation involved. By the definition of cube root, it is 2.

If you were to ask me, "What is the cube root of 7?", I would whip out my calculator and answer that [itex]\sqrt[3]{7}= 1.913[/itex], approximately.
 
Thank you, it was the fundamental understanding I was being a total dumb ass with. . Thanks for your patience and inputs, my old school lessons are finally reawkening from the recesses of my mind, 20 years on!

Greatly appreciated, Darren.
 

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