How Do You Calculate the Mean Radius of a Cylinder?

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SUMMARY

The mean radius, \(\bar{r}\), of a cylinder can be calculated using the formula \(\bar{r} = \frac{1}{4\pi}\int\int r \sin\vartheta d\vartheta d\beta\). For a cylinder with radius \(a\) and height \(h\), where \(a = h/2 = 10 \, \text{cm}\), the limits for \(\beta\) are established as 0 to \(2\pi\) and for \(\theta\) as 0 to \(\pi\). The correct evaluation yields a mean radius of approximately 11.32 cm, as referenced in Attix's textbook. Utilizing cylindrical coordinates (s, φ, z) simplifies the calculation of the distance from the cylinder's center to its boundary surface.

PREREQUISITES
  • Understanding of cylindrical coordinates (s, φ, z)
  • Familiarity with double integrals in calculus
  • Knowledge of surface area averaging techniques
  • Basic concepts of geometry related to cylinders
NEXT STEPS
  • Study the application of double integrals in cylindrical coordinates
  • Learn about surface area averaging formulas in calculus
  • Explore the derivation of mean radius for different geometric shapes
  • Review Attix's textbook for additional examples and explanations
USEFUL FOR

Students in mathematics or engineering courses, particularly those focusing on calculus and geometry, as well as educators seeking to explain the concept of mean radius in cylindrical shapes.

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Homework Statement



I am working a homework problem that is trying to find the mean radius, \bar{r} from the midpoint of a cylinder.

The problem states:
What is the mean radius, \bar{r} from the midpoint of a cylinder of radius a and height h to its boundary surface? Evalute mean radius \bar{r} for a = h/2 = 10 cm.

Homework Equations



The relavent equation is \bar{r} = (1/4pi)\int\int^ r sin\varthetad\varthetad\beta


The Attempt at a Solution


The problem and formula above is from Attix's textbook. In this case I think the limits for beta need to be 0 to 2pi for a cylinder.

I'm not sure what the limits for theta should be. I'm think it's 0 to pi.
I need to express r in terms of theta - but I'm not sure how.

Attix gives the answer as 11.32 cm.

Thanks in advance for any assistance.
 
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I would use cylindrical coordinates (s,\phi,z) if I were you...the distance from the center of the cylinder (the origin) to a general point on the cylinder (s,\phi,z) is then \sqrt{s^2+z^}...then all you need to do is average that over all three surfaces of the cylinder.

What is the general formula for averaging a function over a surface \mathcal{S}?...Use that.
 

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