How do you calculate the power set of a set of sets?

cilla
Messages
13
Reaction score
0
How are you supposed to go about putting together the power set of a set of sets such as
X = {{1},{1,2}}

What is the power set of X then? And what's the rule for calculating cardinality for the power set of a set that consists of elements which are sets such as the above? Because the set X to my understanding has 2 elements, both of which are sets... so the power set of X doesn't consist of only 4 elements, does it?

There are:
{}, {1}, {1,2}, {{1},{1,2}}

Or is that really all?

Please help clarify this to me, thanks so much.
 
Physics news on Phys.org
Yep, that's about it. You only care about finding the subsets of X so the element a_i \in X can be whatever.
 
Actually, the singletons of X here are {{1}} and {{1,2}}. It's a subtle but important distinction.
 
Oh yes, thank you gopher_p (and da_nang). I'm just glad it's not some crazy mix of inner and outer elements.
 
If the iterated set notation confuses you, just do something like ##a = \{1\}, b = \{1, 2\}, X = \{a,b\}## and then at the end substitute back.
 
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Thread 'Detail of Diagonalization Lemma'
The following is more or less taken from page 6 of C. Smorynski's "Self-Reference and Modal Logic". (Springer, 1985) (I couldn't get raised brackets to indicate codification (Gödel numbering), so I use a box. The overline is assigning a name. The detail I would like clarification on is in the second step in the last line, where we have an m-overlined, and we substitute the expression for m. Are we saying that the name of a coded term is the same as the coded term? Thanks in advance.

Similar threads

Replies
18
Views
2K
Replies
2
Views
2K
Replies
13
Views
1K
Replies
5
Views
2K
Replies
1
Views
1K
Back
Top