The discussion focuses on calculating the required thickness of aluminum for a box designed to hold an amplifier weighing 350 grams. The user seeks a formula to determine the appropriate material thickness, specifically mentioning that 1.6mm (16 gauge) is likely suitable. Key equations referenced include M = I and σ = y, with attempts to apply these formulas to derive the necessary thickness based on the load and material properties.
PREREQUISITESEngineers, designers, and hobbyists involved in structural design, particularly those working with aluminum materials for lightweight applications.
SP_RED said:Homework Statement
i am trying to work out the required material thickness for a given box.
the material i am using is aluminium.
i only require the formula - can't find a suitable one on web
Homework Equations
The Attempt at a Solution
M = I
σ y
M = bd M = bd2
σ 12/2 σ 6
SP_RED said:Homework Statement
i am trying to work out the required material thickness (gauge) for a box i am making which is designed to hold an amplifier weighing 350grams.
the material i am using for the boxes is aluminium.
i know that 1.6mm or 16 gauge is more the suitable but i am just trying to prove it through the appliance of science/maths.
i only require the formula - can't find a suitable one on web
Homework Equations
The Attempt at a Solution
M = I
σ y
M = bd M = bd2
σ 12/2 σ 6