How Do You Calculate the Sedimentation Coefficient of Escherichia coli?

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To calculate the sedimentation coefficient of Escherichia coli, the relevant equation involves the molecular weight, specific volume, and other parameters. The user has provided specific data, including molecular weight and specific volume, but is struggling with the terms \(\rho_f\) and \(V_o\) in the equation. They have rearranged the equation to isolate the sedimentation coefficient but encountered a division by zero issue when substituting values. Clarification on how to determine \(\rho_f\) and \(V_o\) is requested without needing a complete solution. Understanding these variables is crucial for successfully calculating the sedimentation coefficient.
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Homework Statement


Escherichia coli data:
molecular weight = 74000g/mol
specific volume = 0.737cm3/g
temperature = 293 K

In a dilute aqueous buffer (0.02M potassium phosphate) at 293.75 K
speed of rotation = 56050 rpm

gave the following results:

Time (min)...x1/2
0.....5.9
20...6
40...6.1
60...6.2
80...6.3
100.....6.4
120.... 6.5
140.....6.6


Homework Equations


This is the equation given to us:

M=(RTs)/(D(1-(\rho f *V o))


The Attempt at a Solution


I used an R value of 8.31m2kgmol-1s-2K-1

I rearranged the equation to equal s

However, I got stuck at \rhof*Vo. Using the \rho and V given in the question results in a division by 0.

Could someone explain to me how I find \rho f and V o? I don't need anyone to solve the question, I would like to do that on my own.
 
Last edited:
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I'm sorry for the terrible equations.
The rho is supposed to be rho with a subscript f, and V is V subscript o
 
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