I don't understand your question. 2 objects in space, each with an individual charge(in coulombs). How do you calculate the "tension" (in voltage)between the two charged entities?mfb said:Nodes where, vacuum where?
That question is much easier to understand than the original post.Cuppasoup said:I don't understand your question. 2 objects in space, each with an individual charge(in coulombs). How do you calculate the "tension" (in voltage)between the two charged entities?
Okay, thanks for the help! By "Calculate the electric field everywhere," do you mean to calculate 2 individual matrices of "tension" depending on the charge and shape of the object and add them together to calculate the resulting electric field?mfb said:That question is much easier to understand than the original post.
Calculate the electric field everywhere (in most cases, to a good approximation: the sum of the fields of two point charges), integrate from one surface to the other.
Oh okay, I guess that means the distinction between "objects" is then blurred.mfb said:If they are close, they will influence the charge distribution of the other object and things get complicated.
Two 1-meter objects with a distance of 0.5 meters between them are clearly different objects, but their charge distributions will influence each other significantly.Cuppasoup said:I guess that means the distinction between "objects" is then blurred.
This is not a matrix, it is a vector field. If you can approximate the charge distribution as spherical, do that. Some other shapes might have analytic solutions, the general case can be treated with numerical methods.Cuppasoup said:So how do I calculate an electric field matrix?
Ok, so to start off in 2D with a circle, if I were to calculate a vector field surrounding a charged "point" in the origin, is there a formula to calculate each vector by its coordinate in relation to the charge of the point?mfb said:This is not a matrix, it is a vector field. If you can approximate the charge distribution as spherical, do that.
The formula for calculating voltage, also known as potential difference, between two charged nodes is V = k * (Q/r), where V is the voltage, k is the Coulomb's constant (9 x 10^9 N*m^2/C^2), Q is the charge of the two nodes, and r is the distance between the two nodes.
The direction of voltage between two charged nodes is determined by the polarity of the charges. If the charges are of the same sign, the voltage will be positive and the direction will be from the higher potential node to the lower potential node. If the charges are of opposite signs, the voltage will be negative and the direction will be from the lower potential node to the higher potential node.
Yes, voltage can be negative. As mentioned in the previous answer, if the charges of two nodes are of opposite signs, the voltage between them will be negative. This indicates a flow of electricity from the lower potential node to the higher potential node.
The voltage between two charged nodes is inversely proportional to the distance between them. This means that as the distance increases, the voltage decreases and vice versa. This relationship is described by the inverse square law, which states that the voltage is proportional to 1/r^2, where r is the distance between the two nodes.
Yes, voltage can be affected by the type of charge or material of the nodes. Different materials have different electrical properties, such as conductivity and permittivity, which can affect the voltage between them. The type of charge also plays a role, as positive and negative charges have different properties and interactions with each other.