How Do You Calculate the Volume and Weight of Air in a Building?

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To calculate the volume and weight of air in a building measuring 40.0 m x 20.0 m x 11.0 m, the volume is found to be 8800 m³, which converts to approximately 28873 ft³. The weight of the air is calculated using the density of 1.20 kg/m³, resulting in a mass of 960 kg, which converts to about 2116 lb, not 1840 lb as initially stated. The importance of maintaining unit consistency throughout calculations is emphasized, particularly during conversions. Additionally, the conversion factor of 2 lb/kg for weight needs verification, as it may not be accurate. Calculations should always be double-checked for accuracy and unit correctness.
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Hi everyone,

Could someone please help me with this problem?

Homework Statement



A building is 40.0 m X 20.0 m X 11.0 m. The density of air is 1.20 kg/m^3. (A) What is the volume of the building in cubic feet? (B) What is the weight of air in the room in pounds?


Homework Equations


Density=mass/volume
1kg is about 2lb
V=lhw
1m=3.281ft

The Attempt at a Solution



a. (40.0 m)(20.0 m)=
800.00 m^2
3
(8.00 X 10^2 m^2)(11.0 m)=
8800m^3

8800m^3(3.281ft/m^3)=
28872.8=
28873 or 2.89 x 10^4 ft^3

b.

m=(1.20kg/m^3)(800m^3)
=960 kg
960kg(2lb/kg)=
1840 lb

Could someone please tell me if this is correct and if not show me where I made my mistake?

Thank you very much
 
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So, I'll start you on part a. The answer is not correct. Whenever you do calculations, it helps to always include all the units and do the same operations on the units as you do on the numeric part. At the end, look at your units and see if that's what you set out to do. Go back and try the conversion again and look at what you have to do to get ft^3 via calculation.

In part b, where did you get the conversion factor 2 lb/kg? Please recheck that.
 
Thank you very much

Regards
 
The weight would just be the volume times the density, right?

Thank you very much
 
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