How Do You Calculate the Volume of a Solid Rotated Around x=2?

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Homework Help Overview

The discussion revolves around calculating the volume of a solid formed by rotating an area enclosed by the curves y=x^(1/2) and y=x^4 about the line x=2. Participants are exploring the methods for determining both the area and the subsequent volume of the solid.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss slicing the volume into horizontal "washers" and integrating to find the volume. There are mentions of using "disks" for volume calculations and subtracting the results from different curves. Some participants question the limits of integration, suggesting they should be from 0 to 1.

Discussion Status

The discussion is active, with participants offering various approaches to the volume calculation. There is some agreement on the limits of integration, but no consensus on the final method for calculating the volume around x=2 has been reached.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is an emphasis on understanding the setup and reasoning behind the calculations rather than arriving at a final answer.

joe007
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Volume Of solids question help!

Homework Statement



i) find the area enclosed by the curves y=x^1/2 and y=x^4
ii)find the volume of the solid when the area in part (i) is rotated about the the line x=2

Homework Equations


V=PI*y^2dx


The Attempt at a Solution


wel the area is simple integral 0 to1 root x -x^.5 and i got 7/15

but I am not sure how to calculate the volume about x=2
 
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hi joe007! :smile:
joe007 said:
ii)find the volume of the solid when the area in part (i) is rotated about the the line x=2

slice the volume into horizontal "washers" of height dy, and integrate :wink:
 


Equivalent to "washers": Use "disks" to find the volume when y= x^{1/2} is rotated around the x-axis, then use "disks" to find the volume when y= x^4 is rotated around the x-axis, and subtract.
 


so its V=2PI* (integral 0 to 2) (x-2)x^0.5 -(x-2)x^4 dx
 


i think it should be from 0 to 1
 


joe007 said:
i think it should be from 0 to 1
Correct !
 

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