How Do You Calculate the Wavelength of Sound Waves Emitted by a Violin String?

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To calculate the wavelength of sound waves emitted by a violin string, the fundamental frequency is essential. The speed of sound in air is 343 m/s, and the frequency of the sound wave is the same as the fundamental frequency of the string, which is 920 Hz. Using the equation λν = c, where λ is the wavelength, ν is the frequency, and c is the speed of sound, the wavelength of the sound waves can be found as λ = c/ν. This results in a wavelength of approximately 37.3 cm for the sound waves emitted by the string. The discussion highlights the importance of understanding wave properties and relationships in physics.
omiexstrike
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I am doing this problem:

(a) Find the speed of waves on a violin string of mass 800 mg and length 22.0 cm if the fundamental frequency is 920 Hz. (b) What is the tension in the string? For the fundamental, what is the wavelength of (c) the waves on the string and (d) the sound waves emitted by the string? (Take the speed of sound in air to be 343 m/s.)

I completed parts a), b), and c), however, I don't know what to do for d).

a)

wavelength = 2L
= 2 (0.22m) = 0.44 m
f= 920 hz

L = wavelength/2
v = f(wavelength)
v=2Lf
= 2(0.22)(920) = 405 m/s

b)

T=(2lf)^2(m/L)

T= 596N

c) wavelength = 2l
= 2 (0.22m) = 0.44m --> 44.0 cm

d) ?

The answers are : a) 405 m/s b) 596 N c) 44.0 cm d) 37.3 cm

I don't know how to arrive for the answer in d).

Thanks for any help.
 
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omiexstrike said:
I am doing this problem:

(a) Find the speed of waves on a violin string of mass 800 mg and length 22.0 cm if the fundamental frequency is 920 Hz. (b) What is the tension in the string? For the fundamental, what is the wavelength of (c) the waves on the string and (d) the sound waves emitted by the string? (Take the speed of sound in air to be 343 m/s.)

I completed parts a), b), and c), however, I don't know what to do for d).

a)

wavelength = 2L
= 2 (0.22m) = 0.44 m
f= 920 hz

L = wavelength/2
v = f(wavelength)
v=2Lf
= 2(0.22)(920) = 405 m/s

b)

T=(2lf)^2(m/L)

T= 596N

c) wavelength = 2l
= 2 (0.22m) = 0.44m --> 44.0 cm

d) ?

The answers are : a) 405 m/s b) 596 N c) 44.0 cm d) 37.3 cm

I don't know how to arrive for the answer in d).

Thanks for any help.

What is the frequency of the sound wave in air?


ehild
 
omiexstrike said:
I don't know how to arrive for the answer in d).

Thanks for any help.

Does the equation ##\lambda \nu = c## look familiar?
 
I got it, thanks guys. =)
 
I guess We can use f=v/2L
 
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