How Do You Calculate Uncertainty in Mean Difference?

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selsunblue
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Homework Statement



321321.png


Homework Equations



Mean difference and SEM

The Attempt at a Solution



Would the mean difference be 0.16?. I'm not sure about the answer because they give that much working space, Do I have to find the uncertainty of the difference first and then my answer implement that into my answer to be 0.16 +- (uncertainty)?. How would I calculate the uncertainty of the mean difference? Do I just add the SEM's for both means?
 
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Would the mean difference be 0.16?
Sure. The large working space is a bit odd.
Do I have to find the uncertainty of the difference first and then my answer implement that into my answer to be 0.16 +- (uncertainty)?
That is part (ii).
How would I calculate the uncertainty of the mean difference? Do I just add the SEM's for both means?
No. Use the method (hopefully) described in section 1.5.
 
selsunblue said:
Do I just add the SEM's for both means?

Here are the basic rules for uncertainty:

Addition/Subtraction
$$(A ± ΔA) + (B ± ΔB) = (A+B) ± (ΔA+ΔB)$$
$$(A ± ΔA) - (B ± ΔB) = (A-B) ± (ΔA+ΔB)$$

When dividing and multiplying, changing to relative uncertainty, then converting back simplifies things.
where: $$ε = \frac{ΔA}{A}*100$$ 'relative uncertainty'

$$(A ± ΔA) / (B ± ΔB) = (A/B) ± (ε_A+ε_B)$$
$$(A ± ΔA)(B ± ΔB) = (AB) ± (ε_A+ε_B)$$

Then you can convert back to abs. uncertainty.
 
vanceEE said:
Here are the basic rules for uncertainty:

Addition/Subtraction
$$(A ± ΔA) + (B ± ΔB) = (A+B) ± (ΔA+ΔB)$$
$$(A ± ΔA) - (B ± ΔB) = (A-B) ± (ΔA+ΔB)$$
Are you sure? I believe the uncertainties should not simply be added, but added in quadrature. That is, if
[tex]x = au \pm bv,[/tex]
then
[tex]\sigma_x^2 = a^2 \sigma_u^2 + b^2 \sigma_v^2.[/tex]
This comes from the basic definition: If [itex]x[/itex] is a function of measured variables [itex]u, v, \ldots[/itex],
[tex]x = f(u, v, \ldots),[/tex]
then,
[tex]\sigma_x^2 \approx \sigma_u^2 \left ( \frac{\partial x}{\partial u}<br /> \right )^2 + \sigma_v^2 \left ( \frac{\partial x}{\partial v} \right )^2 + \ldots \;.[/tex]

I did not check your other equations.
 
Yes, in general the uncertainties should be added in quadrature, if correlations are not important.

A linear addition is sometimes used as worst case estimate to include possible correlations between the uncertainties. We take the difference between measured heights here - there is no way the uncertainties could be correlated "the wrong way" (e. g. a systematic deviation towards larger men and smaller women at the same time).