How Do You Calculate Uncertainty in the Function f(x,z)=z/x?

AI Thread Summary
To calculate the uncertainty in the function f(x,z)=z/x, the appropriate formula for uncertainty is Δf(x,y)² = (∂f/∂x)²Δx² + (∂f/∂y)²Δy². The user initially attempted to use an incorrect expression for the uncertainty, leading to mismatched units. It was pointed out that the derivative of 1/x is not ln|x|, which clarified the confusion. Proper application of the derivative and uncertainty formula is essential for accurate results. Understanding these calculations is crucial for resolving the uncertainty in the function.
glasshut137
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Homework Statement



Calculate "f" and its uncertainty, watch the units, show all work.

Homework Equations



f(x,z)= z/x
x=100.5(+ or -) 3.8 cm
y=71(+ or -) 1 s

The Attempt at a Solution



ok so i know that to find uncertainty i have to use the equation delta f(x,y)=df(x,y)/dx *(delta x) + df(x,y)/dy * delta y. I got (delta f)= z*lnx*(delta x) + (delta z)/x. When i plug in the numbers the units don't match up, i get cm*s + s/cm.

im really confused on how to find the answer can someone please help. thanks.
 
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glasshut137 said:
delta f(x,y)=df(x,y)/dx *(delta x) + df(x,y)/dy * delta y]
That is not correct. In general:

\left(\Delta f(x,y)\right)^2 = \left(\frac{\partial f}{\partial x}\right)^2\Delta x^2 + \left(\frac{\partial f}{\partial y}\right)^2\Delta y^2

glasshut137 said:
I got (delta f)= z*lnx*(delta x) + (delta z)/x
This is also in correct.

\frac{d}{dx}\left(\frac{1}{x}\right) \neq \ln|x|
 
Last edited:
oh jeez you're right thanks
 
glasshut137 said:
oh jeez you're right thanks
Take a note of my further comment, which was added after you replied.
 
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