How Do You Calculate Wave Speed Using the Wave Equation?

AI Thread Summary
To calculate wave speed using the wave equation, the given wave function y(x,t) = (3.00 mm) sin [(4.00/m)x - (7.0/s)t] needs to be analyzed. The wave equation states that the second derivatives with respect to space and time are related through the wave speed v. Users are advised to take the second derivatives of the wave function with respect to both x and t to find the necessary values. The relationship v = ω/k should yield consistent results for wave speed, where ω is the angular frequency and k is the wave number. Proper application of these principles will lead to the correct calculation of wave speed.
Ishu
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Wave Equation problem..! Help...!

Hi can anyone solve this??
I couldn't figure out how to use it

Question
Use the wave equation to find the speed of wave given by

y(x,t)=(3.00 mm) sin [(4.00/m)x-(7.0/s)t) ]





I guess the wave equation is ,

(d^2y) 1 (d^2y)
------- = ------ -------
(dx^2) v^2 (dt^2)


can anyone solve it step wise?
 
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Ishu said:
can anyone solve it step wise?

Not really, no. That's not quite how stuff's done on this forum. You're supposed to do the work yourself.

The wave equation:
\frac{\partial ^2 y}{\partial x^2} = \frac{1}{v^2}\frac{\partial ^2 y}{\partial t^2}

For the given wave, can you solve
\frac{\partial ^2 y}{\partial x^2} and \frac{\partial ^2 y}{\partial t^2} ?
 
I mean need some hint...

please I ahve 1 more hrs left
 
Am i suppose to t6ake second derivative of whole equation...twice? once with respect to t and again with respect to x?
is that how I am supposed to do?
 
Ishu said:
Am i suppose to t6ake second derivative of whole equation...twice? once with respect to t and again with respect to x?
is that how I am supposed to do?
Yep, that's what you're supposed to do.
 
that means I am supposed to solve for "V" right?

But the answer I got is not the same as the one I got from V=w/k

??
 
Ishu said:
that means I am supposed to solve for "V" right?
But the answer I got is not the same as the one I got from V=w/k
??
It should be the same, as the equation reduces to v = \frac{\omega}{k}
 
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