How Do You Calculate Wire Resistivity in Physics Homework?

AI Thread Summary
To calculate the resistivity of a wire, use the formula p = ra/l, where p is resistivity, r is resistance, a is cross-sectional area, and l is length. The resistance has already been calculated as 1.5 ohms, with the wire's length at 2.5 meters and cross-sectional area at 2.0 mm². Rearranging the original equation r = pl/a allows for the calculation of resistivity by substituting the known values. It's important to practice rearranging equations to build confidence in solving physics problems. Understanding these concepts will aid in completing physics homework effectively.
thunderstorm
hi, i am doing my physics homework at the moment, and i have got stuck on the last part of a question. it is asking for the resistivity of the wire- the values i have are
length of wire 2.5m, cross sectional area 2.0mm squared, current of 3.0a flowing through driven by p.d. of 4.5V. the first part of the question had me work out the resistance of the wire which i got as 1.5ohms.
i understand the equation for resistivity is
r= pl/a where p is the resistivity, l is length, a is area of wire and r is resistance?
so do i rearrange this equation to work it out? sorry for sounding stupid, i get confused easily and I'm not very good at rearranging equations, any tips? thanks
 
Physics news on Phys.org


Hi there,

No need to apologize, we all have trouble with certain concepts and equations at times. It's great that you have already calculated the resistance of the wire, as that is an important part of finding the resistivity.

To rearrange the equation, you can follow these steps:

1. Start with the equation r = pl/a
2. Multiply both sides by a: ra = pl
3. Divide both sides by l: ra/l = p
4. Rearrange the equation to isolate p: p = ra/l

Now you can plug in the values you have for resistance (r), length (l), and area (a) to solve for the resistivity (p).

I hope this helps! Don't be too hard on yourself, rearranging equations can be tricky but with practice, it will become easier. Keep up the good work on your physics homework!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top