How Do You Complete the Square for x^2 + 3x + 4?

  • Thread starter Thread starter iNsChris
  • Start date Start date
  • Tags Tags
    Complete Square
iNsChris
Messages
22
Reaction score
0
Complete the square - Help please :)

Not to good with fractions, so I'm posting this here.


x^2 + 3x +4

Complete the square.

Ill try:

(x + 3/6)^2 + ?

lol best i can do sorry :)

Thanks
 
Mathematics news on Phys.org
iNsChris said:
Not to good with fractions, so I'm posting this here.


x^2 + 3x +4

Complete the square.

Ill try:

(x + 3/6)^2 + ?

lol best i can do sorry :)

Thanks

x^2 + 3x + 4
=> (x + 1.5)^2 +4 - 2.25
=> (x + 1.5)^2 +1.75

There you go.

The Bob (2004 ©)
 
yeh i considered decimals but book showed fractions - Cheers mate.
 
iNsChris said:
yeh i considered decimals but book showed fractions - Cheers mate.

What is that supposed to mean? It makes no difference how you express the numbers (every fraction has some decimal representation!), the method of solving the problem is always the same.

x^2 + 3x +4 = \left(x + \frac{3}{2}\right)^2 + 4 - \left(\frac{3}{2}\right)^2

Do you see the general procedure for completing the square? It's always the same. Think about what it means to "complete the square". We want to add 'something' to the expression so that we end up with a perfect square. (and then subtract that same 'something' so that in the end we haven't changed anything). i.e. so that

x^2 + 3x + something + 4 - something

can be expressed using the square of some binomial (ie so that the italicized part is a perfect square):

= (x + ?)^2 +4 - something

Can you see that '?' must be half of 3 in this case? -- because when you expand, you get x^2 + 2?x + ?^2
so (2? = 3)

It follows that 'something' = ?^2 = (3/2)^2 = 9/4

So if you understand and follow this reasoning every single time, completing the square will never be any trouble.


btw last time I checked:

3/2 = 1.5

9/4 = 2.25

:wink:
 
for the function, actually there's an easier way to complete the square, just simply expand it out, what i mean is

x^3+3x+4=a(x+b)^2+c

equate these 2 together, expand out a(x+b)^2+c then compare the coefficients.
 
I believe Chris understands this but thought that he had to use fractions when really decimals were alright.

The completing the square process is simple and he has it but it was a little doubt that needed sorting.

The Bob (2004 ©)
 
Bob's right. Fractions always get people. It took me quite a while to get used to them myself.
 

Similar threads

Replies
13
Views
1K
Replies
5
Views
2K
Replies
6
Views
2K
Replies
18
Views
4K
Replies
10
Views
2K
Replies
2
Views
1K
Back
Top