iNsChris said:
yeh i considered decimals but book showed fractions - Cheers mate.
What is that supposed to mean? It makes no difference how you express the numbers (every fraction has some decimal representation!), the method of solving the problem is always the same.
x^2 + 3x +4 = \left(x + \frac{3}{2}\right)^2 + 4 - \left(\frac{3}{2}\right)^2
Do you see the general procedure for completing the square? It's
always the same. Think about what it means to "complete the square". We want to add 'something' to the expression so that we end up with a
perfect square. (and then subtract that same 'something' so that in the end we haven't changed anything). i.e. so that
x^2 + 3x + something + 4 - something
can be expressed using the square of some binomial (ie so that the italicized part is a perfect square):
= (x + ?)^2 +4 - something
Can you see that '?' must be half of 3 in this case? -- because when you expand, you get x^2 + 2?x + ?^2
so (2? = 3)
It follows that 'something' = ?^2 = (3/2)^2 = 9/4
So if you understand and follow this reasoning every single time, completing the square will never be any trouble.
btw last time I checked:
3/2 = 1.5
9/4 = 2.25
