How Do You Compute Var(X-2Y) When X and Y Are Not Independent?

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To compute Var(X-2Y) when X and Y are not independent, the correct formula to use is Var(X-2Y) = Var(X) + 4Var(Y) + 2Cov(X,Y). Given that Var(X) is 9 and Var(Y) is 1, the formula simplifies to Var(X-2Y) = 9 + 4(1) + 2Cov(X,Y). The value of Cov(X,Y) is crucial for the final calculation, and clarification on p(X,Y) is needed for a complete understanding. This approach highlights the importance of covariance in determining the variance of linear combinations of random variables.
hanelliot
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Studying for an intro course test and I have no one to compare it to right now.. any help would be appreciated.

Here is the question.

Q. Suppose X and Y are random variables such that p(X,Y)=1/3, Var(X) = 9 and Var(Y) = 1. Compute Var(X-2Y).

Since X and Y are not independent, we are using this formula: Var(X-Y) = Var(X) + Var(Y) - 2Cov(X,Y), correct?
So, Var(X-2Y) = Var(X) - 4Var(Y) - 2Cov(X,Y)? How do I proceed from here?
 
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Hi, you may want to clarify what exactly p(X,Y) means here.
 
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