How Do You Correctly Derive (-x^2/18)?

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To derive (-x^2/18), it's recommended to rewrite the function as (-1/18)x^2, allowing the use of the power rule for differentiation. The correct derivative is obtained as (2/18)x, simplifying to x/9. The discussion emphasizes avoiding the quotient rule when the denominator is a constant, as it complicates the process and increases the chance of errors. Additionally, using the constant multiple rule is advised when dealing with constants in derivatives. The final consensus is that the power rule is the most straightforward method for this type of function.
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Can someone please show me how to get the derivative of (-x^2/18). I know the answer is x/9 but I use the quotient rule and keep getting (x^2-36x)/18^2

Thanks b
 
Last edited:
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Instead of using the quotient rule, try writing the function as:

\frac{1}{18}x^2

Now it is just a power rule derivative. Does that help?

Not that the quotient rule doesn't work, though. From your answer, it looks like you're doing it incorrectly. Remember that the quotient rule is:
\frac{d}{dx}\frac{f(x)}{g(x)}=\frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}
 
Last edited:
So I did (1/18)(x^2)

To get 2x(1)+(1/18)(x^2)

2x+(x^2/18)

(36x+x^2)/18

what can i do after that step?
 
You're using the power rule incorrectly also. The power rule is:
\frac{d}{dx}cx^n=ncx^{n-1}Edit: Ah, it looks you are trying to do the product rule. Remember that if you have any constant times x or x divided by a constant, you can use the power rule instead of the product or quotient rules.

Remember that the derivative of a constant term is 0, not 1!

Still, once again, the power rule does work in this case. It is:
\frac{d}{dx}f(x)g(x)=f'(x)g(x)+f(x)g'(x)
 
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whoops it should have been -x^2+36x/18^2 for the quotient rule
 
Yea thanks I just had a small mental break down was making stupid mistakes
I get (18x^2+2x)/18
 
Let's try this first:

What is \frac{d}{dx}x^2 ?
 
Xishem said:
Let's try this first:

What is \frac{d}{dx}x^2 ?

it would be 2x
 
Hemolymph said:
So I did (1/18)(x^2)

To get 2x(1)+(1/18)(x^2)

2x+(x^2/18)

(36x+x^2)/18

what can i do after that step?

What is
\frac{d}{dx} \left(\frac{1}{18}\right) \, ?

RGV
 
  • #10
Ray Vickson said:
What is
\frac{d}{dx} \left(\frac{1}{18}\right) \, ?

RGV

a constant so one
 
  • #11
The derivative of a constant is 0.
 
  • #12
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  • #13
Xishem said:
The derivative of a constant is 0.

WOW I am such a fool...
 
  • #14
alright I got it now...(2x/18)=x/9

Thanks everyone for your help much appreciated
 
  • #15
A couple more points that weren't brought up in this thread:

1. You should never use the quotient rule if the denominator is a constant. It's not wrong to use the quotient rule, but it's more complicated, which makes it more likely that you will make a mistake.

For example, if f(x) = x2/4, write this as (1/4)x2 and use the constant multiple rule, which says that d/dx(k*f(x)) = k*d/dx(f(x)).
Using this rule we get f'(x) = (1/4) * d/dx(x2) = (1/4) * 2x = x/2

2. You should never use the product rule if one factor is a constant. Instead, use the constant multiple rule. It would not be incorrect to use the product rule, but as before, it's more complicated, so you are more likely to make a mistake.

For example, if g(x) = 10 * tan(x), then g'(x) = 10 * d/dx(tan(x)) = 10 * sec2(x).
 
  • #16
Thanks that definitely helped me
 

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