How Do You Determine Linear Transformations in R^2?

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Homework Statement


If L((1,2)^T) = (-2,3)^T and L((1, -1)T) = (5,2)T determine L((7,5)T)


Homework Equations


If L is a linear transformation mapping a vector V into W, it follows:
L(v1 + v2) = L(v1) +L(v2) (alpha = beta = 1)
and
L (alpha v) = alpha L(v) (v = v1, Beta = 0)


The Attempt at a Solution


I've tried all kind of linear combinations, rotations and reflections, and I just can't get this one. Can someone give a hint?
 
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You first need to write out (7,5) as a linear combination of (1,2) and (1,-1), so you need to find constants a1 and a2 such that
<br /> a_1(1,2) + a_2(1,-1) = (7,5).<br />

Can you turn this into a system of simultaneous equations?
 
Here is another example. L(x) = vector x +x1 = (x1 + x1, x2 + x1)
So L(1,2)^T = (2, 3)^T and L(2, 3)^T = (4, 5). Therefore, the L(3, 4)^T = (6, 7)^T

We are not taking linear combinations of the first 2 vectors to arrive at the third vector.
 
I don't really understand your last post. Writing out the vector to which you are applying L as a linear combination of two other vectors works fine in this example with L(x_1, x_2) = (2x_1, x_1 + x_2):

<br /> a_1 (1,2) + a_2 (2,3) = (3,4)<br />

<br /> a_1 + 2a_2 = 3<br />
<br /> 2a_1 + 3a_2 = 4<br />

Solving this system, I get a1 = -1 and a2 = 2. Then

<br /> L(3,4) = L(-(1,2) + 2(2,3)) = -L(1,2) + 2L(2,3) = -(2,3) + 2(4,5) = (6,7)<br />

as you got before. You can apply the same method to the problem in your original post.
 
This is not a linear combination of two vectors. I need to show a linear operator that takes
(1,2) transposed to (-2, 3). And it takes (1, -1) transposed to (5, 2) transposed.

This is not a linear combination of (1, 2) and (1, -1) problem.
 
It is a linear combination of (1, 2) and (1, -1) problem. If

L((1,2)^{T}) = (-2, 3)^{T},

then what is

L \[ \left( \begin{array}{c}<br /> 1\\<br /> 2\end{array} \right)?
 
IntroAnalysis said:
This is not a linear combination of two vectors. I need to show a linear operator that takes
(1,2) transposed to (-2, 3). And it takes (1, -1) transposed to (5, 2) transposed.

This is not a linear combination of (1, 2) and (1, -1) problem.
It reduces to the latter problem because the operator L is linear. Take a look again at what spamiam did in his or her last post.
 
Thanks for the help.
I see now that 4(1,2)T + 3(1, -1)T = (7, 5)T

Therefore L(7,5)T = 4(-2, 3)T + 3(5, 2)T = (7, 18)T
 
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