How Do You Determine the Extrema of f(x, y) = x + 2y on a Unit Disk?

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Find the maximum and minimum values of f(x,y) = x+2y on the disk
x2+y^2 ≤1

I have this for now:

f_1(x,y) = 1
f_2(x,y) = 2

x=cos(t) and y=sin(t)

I have that g(t) = x(t) + 2*y(t) --> g(t) = cost(t) + 2*sin(t)

g'(t) = 0 = 2*cost-sin(t)

Then I can see that:

2cos(t)/cos(t) -sin(t)/cos(t) = 0/cos(t) --> tan = 2

That is the parameterization, right?

From this point I have no idea what to do.
 
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Kork said:
Find the maximum and minimum values of f(x,y) = x+2y on the disk
x2+y^2 ≤1

I have this for now:

f_1(x,y) = 1
f_2(x,y) = 2

x=cos(t) and y=sin(t)

I have that g(t) = x(t) + 2*y(t) --> g(t) = cost(t) + 2*sin(t)

g'(t) = 0 = 2*cost-sin(t)

Then I can see that:

2cos(t)/cos(t) -sin(t)/cos(t) = 0/cos(t) --> tan = 2

That is the parameterization, right?

From this point I have no idea what to do.

Find the value or values of t that give tan(t) = 2. Or, since you only need sin(t) and cos(t), why not express them in terms of tan(t)?

RGV
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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