How do you determine the wavelength of the string?

  • Thread starter Thread starter ~angel~
  • Start date Start date
  • Tags Tags
    String Wavelength
AI Thread Summary
To determine the wavelength of a string, first calculate the wave velocity using the formula v = √(T/μ), where T is tension and μ is linear density. For a 1m string with a mass of 100g and a tension of 10N, the linear density is 0.1 kg/m, resulting in a wave velocity of 10 m/s. The wavelength can then be found using the relationship v = frequency × wavelength, leading to the calculation of wavelength as 1.05 m when using a frequency of 9.5 Hz. However, a correction was noted regarding the tension value, which should be 1N instead of 10N for accurate results. Understanding these calculations is essential for determining the wavelength accurately.
~angel~
Messages
150
Reaction score
0
There is a string 1m in length, 100g in mass and has tension of 10N. 9.5 Hz of frequency is applied to it.

I know this question is meant to be simple but how do you determine the wavelength of the string?

Thank you.
 
Physics news on Phys.org
The wave velocity is given by the square root of (tension over linear density).
Once you know the wave velocity you can get the wave length from that and the frequency.
 
The wavelength is one over the frequency, so just divide 1 by 9.5 and that tells you the lenghth of one period or the wavelength.
 
HallsofIvy said:
The wave velocity is given by the square root of (tension over linear density).
Once you know the wave velocity you can get the wave length from that and the frequency.

The linear density has units of kg/m, right? So v = 10/0.1^(1/2) = 10m/s. But when this is substituted into v=wavelength*f, the wavelength is 1.05, which doesn't make sense.
 
Ok velocity of wave in a string with tension is given by:

<br /> <br /> v= \sqrt \frac{T}{m}<br /> <br />


where m=mass per unit length.


Now apply v=f(Wavelength) to get the answer
 
I misread the tension (it was meant to be 1N).

Thanks guys.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top