How Do You Determine Zero Potential Locations on the X-axis with Two Charges?

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To determine the zero potential locations on the x-axis with a -1.9 × 10^-9 C charge at the origin and a 9.4 × 10^-9 C charge at x = 3 m, the equation for electric potential must be set up using v = kq/x. The positive potential location is found at x = 0.5 m, while the negative potential location remains unsolved. The challenge lies in calculating the second location, as the potential cannot be zero between a positive and negative charge. Further assistance is requested to establish the correct equation for the negative potential location.
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Homework Statement


A charge of -1.9 × 10-9 C is at the origin and a charge of 9.4 × 10-9 C is on the x-axis at x = 3 m. At what two locations on the x-axis (xpositive, xnegative) is the potential zero?
xpositive = m
Xpositive = .5m
v=kq/x + (k(5Q/3-x))to solve for this value,
.5

xnegative = m
I'm lost on the second part of the problem which we need to calculate the X negative
If someone could help me set this equation up I would be very appreciative :)


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How can the field be 0 on the line between a (+) and a (-) charge?
 
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