- #1
vDrag0n
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Homework Statement
int (1/(4-r^2)^0.5) dr dx, r=0 to 2sinx, x=0 to 2pi
Homework Equations
How to continue the integral of x
The Attempt at a Solution
I'm stuck at
int(arcsin(sinx)) dx, x=0 to 2pi
This is your iterated integral:vDrag0n said:Homework Statement
int (1/(4-r^2)^0.5) dr dx, r=0 to 2sinx, x=0 to 2pi
Homework Equations
How to continue the integral of x
The Attempt at a Solution
I'm stuck at
int(arcsin(sinx)) dx, x=0 to 2pi
A double integral is a type of mathematical calculation used to find the area between a two-dimensional function and a specified region on the x-y plane.
To solve a double integral, you must first evaluate the inner integral with respect to one variable, and then use the result as the integrand for the outer integral. This process is known as "integrating inside-out".
The purpose of solving a double integral is to find the area under a two-dimensional curve over a specified region. This can be useful in a variety of real-world applications, such as calculating volumes or finding the center of mass of an object.
The limits of integration in a double integral represent the boundaries of the region over which the integration is being performed. These limits can be determined by the shape and size of the region, as well as the function being integrated.
Yes, there are a few special techniques that can be used to solve difficult double integrals. These include changing the order of integration, using polar coordinates, and using trigonometric substitutions. It is important to familiarize yourself with these techniques in order to solve more complex double integrals.