# How do you evaluate this log equation?

## Homework Statement

log39 + log41/64 + log51

none

## The Attempt at a Solution

(3x=9) + (4x=1/64) + (5x=1)
because of this, I got 5. Is that correct?

Related Precalculus Mathematics Homework Help News on Phys.org
tiny-tim
Homework Helper
Hi haengbon! (3x=9) + (4x=1/64) + (5x=1)
because of this, I got 5. Is that correct?
Correct method , but wrong result try (4x=1/64) again. Hi haengbon! Correct method , but wrong result try (4x=1/64) again. I tried it again and got -3 for 4x=1/64 :D is that correct now? ^^ thank you for the help by the way :)

tiny-tim
Homework Helper
I tried it again and got -3 for 4x=1/64 :D is that correct now? ^^
Yup! Mark44
Mentor
haengbon said:

(3x=9) + (4x=1/64) + (5x=1)
because of this, I got 5. Is that correct?
If you turn in work like this, your instructor will probably deduct points, since you are apparently trying to add three equations.

Each of the log expressions is simple enough to calculate, so your work should look something like this.

log39 + log41/64 + log51
= 2 - log464 + 0
= 2 - 3 = -1

I used the fact that log(1/x) = - log(x) going from the first expression to the second.