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How do you evaluate this log equation?

  1. Apr 4, 2010 #1
    1. The problem statement, all variables and given/known data

    log39 + log41/64 + log51


    2. Relevant equations
    none


    3. The attempt at a solution

    I tried answering it by...

    (3x=9) + (4x=1/64) + (5x=1)
    because of this, I got 5. Is that correct?
     
  2. jcsd
  3. Apr 4, 2010 #2

    tiny-tim

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    Science Advisor
    Homework Helper

    Hi haengbon! :smile:
    Correct method :smile:, but wrong result :redface:

    try (4x=1/64) again. :wink:
     
  4. Apr 4, 2010 #3
    I tried it again and got -3 for 4x=1/64 :D is that correct now? ^^ thank you for the help by the way :)
     
  5. Apr 4, 2010 #4

    tiny-tim

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    Yup! :biggrin:
     
  6. Apr 4, 2010 #5

    Mark44

    Staff: Mentor

    If you turn in work like this, your instructor will probably deduct points, since you are apparently trying to add three equations.

    Each of the log expressions is simple enough to calculate, so your work should look something like this.

    log39 + log41/64 + log51
    = 2 - log464 + 0
    = 2 - 3 = -1

    I used the fact that log(1/x) = - log(x) going from the first expression to the second.
     
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