- #1

- 38

- 0

## Homework Statement

log

_{3}9 + log

_{4}1/64 + log

_{5}1

## Homework Equations

none

## The Attempt at a Solution

I tried answering it by...

(3

^{x}=9) + (4

^{x}=1/64) + (5

^{x}=1)

because of this, I got 5. Is that correct?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter haengbon
- Start date

- #1

- 38

- 0

log

none

I tried answering it by...

(3

because of this, I got 5. Is that correct?

- #2

tiny-tim

Science Advisor

Homework Helper

- 25,832

- 251

(3^{x}=9) + (4^{x}=1/64) + (5^{x}=1)

because of this, I got 5. Is that correct?

Correct method , but wrong result …

try (4^{x}=1/64) again.

- #3

- 38

- 0

Hi haengbon!

Correct method , but wrong result …

try (4^{x}=1/64) again.

I tried it again and got -3 for 4

- #4

tiny-tim

Science Advisor

Homework Helper

- 25,832

- 251

I tried it again and got -3 for 4^{x}=1/64 :D is that correct now? ^^

Yup!

- #5

Mark44

Mentor

- 34,896

- 6,636

If you turn in work like this, your instructor will probably deduct points, since you are apparently trying to add three equations.haengbon said:I tried answering it by...

(3^{x}=9) + (4^{x}=1/64) + (5^{x}=1)

because of this, I got 5. Is that correct?

Each of the log expressions is simple enough to calculate, so your work should look something like this.

log

= 2 - log

= 2 - 3 = -1

I used the fact that log(1/x) = - log(x) going from the first expression to the second.

Share: