How do you evaluate this log equation?

  • Thread starter haengbon
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  • #1
haengbon
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Homework Statement



log39 + log41/64 + log51


Homework Equations


none


The Attempt at a Solution



I tried answering it by...

(3x=9) + (4x=1/64) + (5x=1)
because of this, I got 5. Is that correct?
 

Answers and Replies

  • #2
tiny-tim
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Hi haengbon! :smile:
(3x=9) + (4x=1/64) + (5x=1)
because of this, I got 5. Is that correct?

Correct method :smile:, but wrong result :redface:

try (4x=1/64) again. :wink:
 
  • #3
haengbon
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Hi haengbon! :smile:


Correct method :smile:, but wrong result :redface:

try (4x=1/64) again. :wink:

I tried it again and got -3 for 4x=1/64 :D is that correct now? ^^ thank you for the help by the way :)
 
  • #4
tiny-tim
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I tried it again and got -3 for 4x=1/64 :D is that correct now? ^^

Yup! :biggrin:
 
  • #5
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haengbon said:
I tried answering it by...

(3x=9) + (4x=1/64) + (5x=1)
because of this, I got 5. Is that correct?
If you turn in work like this, your instructor will probably deduct points, since you are apparently trying to add three equations.

Each of the log expressions is simple enough to calculate, so your work should look something like this.

log39 + log41/64 + log51
= 2 - log464 + 0
= 2 - 3 = -1

I used the fact that log(1/x) = - log(x) going from the first expression to the second.
 

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